2/(16x2x)=48

Solution for 2/(16x2x)=48 equation:

2/(16x^2x)=48

We move all terms to the left:

2/(16x^2x)-(48)=0


Domain of the equation: 16x^2x!=0

x!=0/1

x!=0

x∈R


We multiply all the terms by the denominator


-48*16x^2x+2=0

Wy multiply elements

-768x^2+2=0

a = -768; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-768)·2
Δ = 6144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6144}=\sqrt{1024*6}=\sqrt{1024}*\sqrt{6}=32\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{6}}{2*-768}=\frac{0-32\sqrt{6}}{-1536}
=-\frac{32\sqrt{6}}{-1536}
=-\frac{\sqrt{6}}{-48}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{6}}{2*-768}=\frac{0+32\sqrt{6}}{-1536}
=\frac{32\sqrt{6}}{-1536}
=\frac{\sqrt{6}}{-48}
$