(7-2)-(3t+1)=-3(1-3t)

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Solution for (7-2)-(3t+1)=-3(1-3t) equation: 



(7-2)-(3t+1)=-3(1-3t)

We move all terms to the left:

(7-2)-(3t+1)-(-3(1-3t))=0

We add all the numbers together, and all the variables

-(3t+1)-(-3(-3t+1))+5=0

We get rid of parentheses

-3t-(-3(-3t+1))-1+5=0



We calculate terms in parentheses: -(-3(-3t+1)), so:

-3(-3t+1)

We multiply parentheses

9t-3

Back to the equation:

-(9t-3)



We add all the numbers together, and all the variables

-3t-(9t-3)+4=0

We get rid of parentheses

-3t-9t+3+4=0

We add all the numbers together, and all the variables

-12t+7=0

We move all terms containing t to the left, all other terms to the right

-12t=-7

t=-7/-12

t=7/12

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