(6y-8)(3y+2)=(9y+8)(2y-3)

Solution for (6y-8)(3y+2)=(9y+8)(2y-3) equation:

(6y-8)(3y+2)=(9y+8)(2y-3)

We move all terms to the left:

(6y-8)(3y+2)-((9y+8)(2y-3))=0

We multiply parentheses ..

(+18y^2+12y-24y-16)-((9y+8)(2y-3))=0


We calculate terms in parentheses: -((9y+8)(2y-3)), so:

(9y+8)(2y-3)

We multiply parentheses ..

(+18y^2-27y+16y-24)

We get rid of parentheses

18y^2-27y+16y-24

We add all the numbers together, and all the variables

18y^2-11y-24

Back to the equation:

-(18y^2-11y-24)


We get rid of parentheses

18y^2-18y^2+12y-24y+11y-16+24=0

We add all the numbers together, and all the variables

-1y+8=0

We move all terms containing y to the left, all other terms to the right

-y=-8

y=-8/-1

y=+8