(-1y-1)(6y-5)=(-3y+1)(2y-1)

Solution for (-1y-1)(6y-5)=(-3y+1)(2y-1) equation:

(-1y-1)(6y-5)=(-3y+1)(2y-1)

We move all terms to the left:

(-1y-1)(6y-5)-((-3y+1)(2y-1))=0

We multiply parentheses ..

(-6y^2+5y-6y+5)-((-3y+1)(2y-1))=0


We calculate terms in parentheses: -((-3y+1)(2y-1)), so:

(-3y+1)(2y-1)

We multiply parentheses ..

(-6y^2+3y+2y-1)

We get rid of parentheses

-6y^2+3y+2y-1

We add all the numbers together, and all the variables

-6y^2+5y-1

Back to the equation:

-(-6y^2+5y-1)


We get rid of parentheses

-6y^2+6y^2+5y-6y-5y+5+1=0

We add all the numbers together, and all the variables

-6y+6=0

We move all terms containing y to the left, all other terms to the right

-6y=-6

y=-6/-6

y=1