(4a+3)+3(3a+1)=12(2a+1)

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Solution for (4a+3)+3(3a+1)=12(2a+1) equation:



(4a+3)+3(3a+1)=12(2a+1)
We move all terms to the left:
(4a+3)+3(3a+1)-(12(2a+1))=0
We multiply parentheses
(4a+3)+9a-(12(2a+1))+3=0
We get rid of parentheses
4a+9a-(12(2a+1))+3+3=0
We calculate terms in parentheses: -(12(2a+1)), so:
12(2a+1)
We multiply parentheses
24a+12
Back to the equation:
-(24a+12)
We add all the numbers together, and all the variables
13a-(24a+12)+6=0
We get rid of parentheses
13a-24a-12+6=0
We add all the numbers together, and all the variables
-11a-6=0
We move all terms containing a to the left, all other terms to the right
-11a=6
a=6/-11
a=-6/11

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