(6y-15)=(3y+6)

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Solution for (6y-15)=(3y+6) equation: 



(6y-15)=(3y+6)

We move all terms to the left:

(6y-15)-((3y+6))=0

We get rid of parentheses

6y-((3y+6))-15=0



We calculate terms in parentheses: -((3y+6)), so:

(3y+6)

We get rid of parentheses

3y+6

Back to the equation:

-(3y+6)



We get rid of parentheses

6y-3y-6-15=0

We add all the numbers together, and all the variables

3y-21=0

We move all terms containing y to the left, all other terms to the right

3y=21

y=21/3

y=7

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