1/4z-1/2z=1/2-1

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Solution for 1/4z-1/2z=1/2-1 equation:



1/4z-1/2z=1/2-1
We move all terms to the left:
1/4z-1/2z-(1/2-1)=0
Domain of the equation: 4z!=0
z!=0/4
z!=0
z∈R
Domain of the equation: 2z!=0
z!=0/2
z!=0
z∈R
We get rid of parentheses
1/4z-1/2z+1-1/2=0
We calculate fractions
8z/32z^2+(-4z)/32z^2+(-4z)/32z^2+1=0
We multiply all the terms by the denominator
8z+(-4z)+(-4z)+1*32z^2=0
Wy multiply elements
32z^2+8z+(-4z)+(-4z)=0
We get rid of parentheses
32z^2+8z-4z-4z=0
We add all the numbers together, and all the variables
32z^2=0
a = 32; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·32·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{0}{64}=0$

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