(6y+1)=(21y+13)

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Solution for (6y+1)=(21y+13) equation: 



(6y+1)=(21y+13)

We move all terms to the left:

(6y+1)-((21y+13))=0

We get rid of parentheses

6y-((21y+13))+1=0



We calculate terms in parentheses: -((21y+13)), so:

(21y+13)

We get rid of parentheses

21y+13

Back to the equation:

-(21y+13)



We get rid of parentheses

6y-21y-13+1=0

We add all the numbers together, and all the variables

-15y-12=0

We move all terms containing y to the left, all other terms to the right

-15y=12

y=12/-15

y=-4/5

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