16z=2(-2z+30)

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Solution for 16z=2(-2z+30) equation:



16z=2(-2z+30)
We move all terms to the left:
16z-(2(-2z+30))=0
We calculate terms in parentheses: -(2(-2z+30)), so:
2(-2z+30)
We multiply parentheses
-4z+60
Back to the equation:
-(-4z+60)
We get rid of parentheses
16z+4z-60=0
We add all the numbers together, and all the variables
20z-60=0
We move all terms containing z to the left, all other terms to the right
20z=60
z=60/20
z=3

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