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(6x-5)-x=1/3-2(x+1)
We move all terms to the left:
(6x-5)-x-(1/3-2(x+1))=0
Domain of the equation: 3-2(x+1))!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-2(x+1))!=-3
x∈R
-1x+(6x-5)-(1/3-2(x+1))=0
We get rid of parentheses
-1x+6x-(1/3-2(x+1))-5=0
We multiply all the terms by the denominator
-1x*3-2(x+1))+6x*3-2(x+1))-(1-5*3-2(x+1))=0
We add all the numbers together, and all the variables
-1x*3-2(x+1))+6x*3-2(x+1))-(1-5*3-2(x=0
Wy multiply elements
-3x-2(x+1))+6x*3-2(x+1))-(1-5*3-2(x=0
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