0.8x-11=0/3x+41

Solution for 0.8x-11=0/3x+41 equation:

0.8x-11=0/3x+41

We move all terms to the left:

0.8x-11-(0/3x+41)=0


Domain of the equation: 3x+41)!=0

x∈R


We get rid of parentheses

0.8x-0/3x-41-11=0

We multiply all the terms by the denominator


(0.8x)*3x-41*3x-11*3x-0=0

We add all the numbers together, and all the variables

(+0.8x)*3x-41*3x-11*3x-0=0

We add all the numbers together, and all the variables

(+0.8x)*3x-41*3x-11*3x=0

We multiply parentheses

0x^2-41*3x-11*3x=0

Wy multiply elements

0x^2-123x-33x=0

We add all the numbers together, and all the variables

x^2-156x=0

a = 1; b = -156; c = 0;
Δ = b2-4ac
Δ = -1562-4·1·0
Δ = 24336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{24336}=156$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-156)-156}{2*1}=\frac{0}{2}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-156)+156}{2*1}=\frac{312}{2}
=156
$