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(6x-5)(x-25)=180
We move all terms to the left:
(6x-5)(x-25)-(180)=0
We multiply parentheses ..
(+6x^2-150x-5x+125)-180=0
We get rid of parentheses
6x^2-150x-5x+125-180=0
We add all the numbers together, and all the variables
6x^2-155x-55=0
a = 6; b = -155; c = -55;
Δ = b2-4ac
Δ = -1552-4·6·(-55)
Δ = 25345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-155)-\sqrt{25345}}{2*6}=\frac{155-\sqrt{25345}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-155)+\sqrt{25345}}{2*6}=\frac{155+\sqrt{25345}}{12} $
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