(3x+11)+(4x+3)=(3x-6)

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Solution for (3x+11)+(4x+3)=(3x-6) equation: 



(3x+11)+(4x+3)=(3x-6)

We move all terms to the left:

(3x+11)+(4x+3)-((3x-6))=0

We get rid of parentheses

3x+4x-((3x-6))+11+3=0



We calculate terms in parentheses: -((3x-6)), so:

(3x-6)

We get rid of parentheses

3x-6

Back to the equation:

-(3x-6)



We add all the numbers together, and all the variables

7x-(3x-6)+14=0

We get rid of parentheses

7x-3x+6+14=0

We add all the numbers together, and all the variables

4x+20=0

We move all terms containing x to the left, all other terms to the right

4x=-20

x=-20/4

x=-5

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