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(6x-5)(=2x+1)
We move all terms to the left:
(6x-5)(-(2x+1))=0
We calculate terms in parentheses: +(6x-5)(-(2x+1)), so:We get rid of parentheses
6x-5)(-(2x+1)
determiningTheFunctionDomain 6x-(2x+1)-5)(
We add all the numbers together, and all the variables
6x-(2x+1)
We get rid of parentheses
6x-2x-1
We add all the numbers together, and all the variables
4x-1
Back to the equation:
+(4x-1)
4x-1=0
We move all terms containing x to the left, all other terms to the right
4x=1
x=1/4
x=1/4
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