4(41-22c/72)+118c=11

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Solution for 4(41-22c/72)+118c=11 equation: 



4(41-22c/72)+118c=11

We move all terms to the left:

4(41-22c/72)+118c-(11)=0

We add all the numbers together, and all the variables

4(-22c/72+41)+118c-11=0

We add all the numbers together, and all the variables

118c+4(-22c/72+41)-11=0

We multiply parentheses

118c-88c+164-11=0

We add all the numbers together, and all the variables

30c+153=0

We move all terms containing c to the left, all other terms to the right

30c=-153

c=-153/30

c=-5+1/10

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