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(6x-5)(7x-10)=180
We move all terms to the left:
(6x-5)(7x-10)-(180)=0
We multiply parentheses ..
(+42x^2-60x-35x+50)-180=0
We get rid of parentheses
42x^2-60x-35x+50-180=0
We add all the numbers together, and all the variables
42x^2-95x-130=0
a = 42; b = -95; c = -130;
Δ = b2-4ac
Δ = -952-4·42·(-130)
Δ = 30865
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-95)-\sqrt{30865}}{2*42}=\frac{95-\sqrt{30865}}{84} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-95)+\sqrt{30865}}{2*42}=\frac{95+\sqrt{30865}}{84} $
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