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(3x-2)(2x+30)=180
We move all terms to the left:
(3x-2)(2x+30)-(180)=0
We multiply parentheses ..
(+6x^2+90x-4x-60)-180=0
We get rid of parentheses
6x^2+90x-4x-60-180=0
We add all the numbers together, and all the variables
6x^2+86x-240=0
a = 6; b = 86; c = -240;
Δ = b2-4ac
Δ = 862-4·6·(-240)
Δ = 13156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{13156}=\sqrt{4*3289}=\sqrt{4}*\sqrt{3289}=2\sqrt{3289}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(86)-2\sqrt{3289}}{2*6}=\frac{-86-2\sqrt{3289}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(86)+2\sqrt{3289}}{2*6}=\frac{-86+2\sqrt{3289}}{12} $
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