(6x-4)-3(5x+2)=7

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Solution for (6x-4)-3(5x+2)=7 equation: 



(6x-4)-3(5x+2)=7

We move all terms to the left:

(6x-4)-3(5x+2)-(7)=0

We multiply parentheses

(6x-4)-15x-6-7=0

We get rid of parentheses

6x-15x-4-6-7=0

We add all the numbers together, and all the variables

-9x-17=0

We move all terms containing x to the left, all other terms to the right

-9x=17

x=17/-9

x=-1+8/9

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