2(n+4)=3(2n-6)

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Solution for 2(n+4)=3(2n-6) equation: 



2(n+4)=3(2n-6)

We move all terms to the left:

2(n+4)-(3(2n-6))=0

We multiply parentheses

2n-(3(2n-6))+8=0



We calculate terms in parentheses: -(3(2n-6)), so:

3(2n-6)

We multiply parentheses

6n-18

Back to the equation:

-(6n-18)



We get rid of parentheses

2n-6n+18+8=0

We add all the numbers together, and all the variables

-4n+26=0

We move all terms containing n to the left, all other terms to the right

-4n=-26

n=-26/-4

n=6+1/2

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