(6x-4)+8=(17-x)=8

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Solution for (6x-4)+8=(17-x)=8 equation: 



(6x-4)+8=(17-x)=8

We move all terms to the left:

(6x-4)+8-((17-x))=0

We add all the numbers together, and all the variables

(6x-4)-((-1x+17))+8=0

We get rid of parentheses

6x-((-1x+17))-4+8=0



We calculate terms in parentheses: -((-1x+17)), so:

(-1x+17)

We get rid of parentheses

-1x+17

Back to the equation:

-(-1x+17)



We add all the numbers together, and all the variables

6x-(-1x+17)+4=0

We get rid of parentheses

6x+1x-17+4=0

We add all the numbers together, and all the variables

7x-13=0

We move all terms containing x to the left, all other terms to the right

7x=13

x=13/7

x=1+6/7

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