3/4(8x-4)=4-1/2(6+2x)

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Solution for 3/4(8x-4)=4-1/2(6+2x) equation: 



3/4(8x-4)=4-1/2(6+2x)

We move all terms to the left:

3/4(8x-4)-(4-1/2(6+2x))=0



Domain of the equation: 4(8x-4)!=0

x∈R





Domain of the equation: 2(6+2x))!=0

x∈R



We add all the numbers together, and all the variables

3/4(8x-4)-(4-1/2(2x+6))=0

We calculate fractions


(6x2/(4(8x-4)*2(2x+6)))+(-(-4x8)/(4(8x-4)*2(2x+6)))=0



We calculate terms in parentheses: +(6x2/(4(8x-4)*2(2x+6))), so:

6x2/(4(8x-4)*2(2x+6))

We multiply all the terms by the denominator


6x2

We add all the numbers together, and all the variables

6x^2

Back to the equation:

+(6x^2)





We calculate terms in parentheses: +(-(-4x8)/(4(8x-4)*2(2x+6))), so:

-(-4x8)/(4(8x-4)*2(2x+6))

We add all the numbers together, and all the variables

-(-4x^8)/(4(8x-4)*2(2x+6))

We multiply all the terms by the denominator


-(-4x^8)

We do not support expression: x^8

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