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(6x-4)(6x+5)=0
We multiply parentheses ..
(+36x^2+30x-24x-20)=0
We get rid of parentheses
36x^2+30x-24x-20=0
We add all the numbers together, and all the variables
36x^2+6x-20=0
a = 36; b = 6; c = -20;
Δ = b2-4ac
Δ = 62-4·36·(-20)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-54}{2*36}=\frac{-60}{72} =-5/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+54}{2*36}=\frac{48}{72} =2/3 $
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