1x+2=4(x+2)

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Solution for 1x+2=4(x+2) equation: 



1x+2=4(x+2)

We move all terms to the left:

1x+2-(4(x+2))=0

We add all the numbers together, and all the variables

x-(4(x+2))+2=0



We calculate terms in parentheses: -(4(x+2)), so:

4(x+2)

We multiply parentheses

4x+8

Back to the equation:

-(4x+8)



We get rid of parentheses

x-4x-8+2=0

We add all the numbers together, and all the variables

-3x-6=0

We move all terms containing x to the left, all other terms to the right

-3x=6

x=6/-3

x=-2

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