(6x-3)(1-2x)+(3-4x)(2-3x)=0

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Solution for (6x-3)(1-2x)+(3-4x)(2-3x)=0 equation: 



(6x-3)(1-2x)+(3-4x)(2-3x)=0

We add all the numbers together, and all the variables

(6x-3)(-2x+1)+(-4x+3)(-3x+2)=0

We multiply parentheses ..

(-12x^2+6x+6x-3)+(-4x+3)(-3x+2)=0

We get rid of parentheses

-12x^2+6x+6x+(-4x+3)(-3x+2)-3=0

We multiply parentheses ..

-12x^2+(+12x^2-8x-9x+6)+6x+6x-3=0

We add all the numbers together, and all the variables

-12x^2+(+12x^2-8x-9x+6)+12x-3=0

We get rid of parentheses

-12x^2+12x^2-8x-9x+12x+6-3=0

We add all the numbers together, and all the variables

-5x+3=0

We move all terms containing x to the left, all other terms to the right

-5x=-3

x=-3/-5

x=3/5

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