(6x-2x+5)=(2x2-7x-11)

Solution for (6x-2x+5)=(2x2-7x-11) equation:

(6x-2x+5)=(2x^2-7x-11)

We move all terms to the left:

(6x-2x+5)-((2x^2-7x-11))=0

We add all the numbers together, and all the variables

(4x+5)-((2x^2-7x-11))=0

We get rid of parentheses

4x-((2x^2-7x-11))+5=0


We calculate terms in parentheses: -((2x^2-7x-11)), so:

(2x^2-7x-11)

We get rid of parentheses

2x^2-7x-11

Back to the equation:

-(2x^2-7x-11)


We get rid of parentheses

-2x^2+4x+7x+11+5=0

We add all the numbers together, and all the variables

-2x^2+11x+16=0

a = -2; b = 11; c = +16;
Δ = b2-4ac
Δ = 112-4·(-2)·16
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{249}}{2*-2}=\frac{-11-\sqrt{249}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{249}}{2*-2}=\frac{-11+\sqrt{249}}{-4}
$