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5(y-6)=4(y-7)
We move all terms to the left:
5(y-6)-(4(y-7))=0
We multiply parentheses
5y-(4(y-7))-30=0
We calculate terms in parentheses: -(4(y-7)), so:We get rid of parentheses
4(y-7)
We multiply parentheses
4y-28
Back to the equation:
-(4y-28)
5y-4y+28-30=0
We add all the numbers together, and all the variables
y-2=0
We move all terms containing y to the left, all other terms to the right
y=2
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