(6x-28)=(7x-40)

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Solution for (6x-28)=(7x-40) equation: 



(6x-28)=(7x-40)

We move all terms to the left:

(6x-28)-((7x-40))=0

We get rid of parentheses

6x-((7x-40))-28=0



We calculate terms in parentheses: -((7x-40)), so:

(7x-40)

We get rid of parentheses

7x-40

Back to the equation:

-(7x-40)



We get rid of parentheses

6x-7x+40-28=0

We add all the numbers together, and all the variables

-1x+12=0

We move all terms containing x to the left, all other terms to the right

-x=-12

x=-12/-1

x=+12

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