3x/3x+4+2/5=x/3x-4

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Solution for 3x/3x+4+2/5=x/3x-4 equation: 



3x/3x+4+2/5=x/3x-4

We move all terms to the left:

3x/3x+4+2/5-(x/3x-4)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 3x-4)!=0

x∈R



We get rid of parentheses

3x/3x-x/3x+4+4+2/5=0

Fractions to decimals

-x/3x+4+4+1+2/5=0

We calculate fractions


(-5x)/15x+6x/15x+4+4+1=0

We add all the numbers together, and all the variables

(-5x)/15x+6x/15x+9=0

We multiply all the terms by the denominator


(-5x)+6x+9*15x=0

We add all the numbers together, and all the variables

6x+(-5x)+9*15x=0

Wy multiply elements

6x+(-5x)+135x=0

We get rid of parentheses

6x-5x+135x=0

We add all the numbers together, and all the variables

136x=0

x=0/136

x=0

Równanie nie ma rozwiązania

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