(6x-2)+(5x+3)-(2x-5)=(7x-1)+(4x+2)-5

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Solution for (6x-2)+(5x+3)-(2x-5)=(7x-1)+(4x+2)-5 equation: 



(6x-2)+(5x+3)-(2x-5)=(7x-1)+(4x+2)-5

We move all terms to the left:

(6x-2)+(5x+3)-(2x-5)-((7x-1)+(4x+2)-5)=0

We get rid of parentheses

6x+5x-2x-((7x-1)+(4x+2)-5)-2+3+5=0



We calculate terms in parentheses: -((7x-1)+(4x+2)-5), so:

(7x-1)+(4x+2)-5

We get rid of parentheses

7x+4x-1+2-5

We add all the numbers together, and all the variables

11x-4

Back to the equation:

-(11x-4)



We add all the numbers together, and all the variables

9x-(11x-4)+6=0

We get rid of parentheses

9x-11x+4+6=0

We add all the numbers together, and all the variables

-2x+10=0

We move all terms containing x to the left, all other terms to the right

-2x=-10

x=-10/-2

x=+5

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