m/0.6m+3=2m+0.2

Solution for m/0.6m+3=2m+0.2 equation:

m/0.6m+3=2m+0.2

We move all terms to the left:

m/0.6m+3-(2m+0.2)=0


Domain of the equation: 0.6m!=0

m!=0/0.6

m!=0

m∈R


We get rid of parentheses

m/0.6m-2m-0.2+3=0

We multiply all the terms by the denominator


m-2m*0.6m-(0.2)*0.6m+3*0.6m=0

We multiply parentheses

m-2m*0.6m-0m+3*0.6m=0

Wy multiply elements

0m^2+m-0m+0m=0

We add all the numbers together, and all the variables

m^2+m=0

a = 1; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·1·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*1}=\frac{-2}{2}
=-1
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*1}=\frac{0}{2}
=0
$