(6x-19)=(3x+10)

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Solution for (6x-19)=(3x+10) equation: 



(6x-19)=(3x+10)

We move all terms to the left:

(6x-19)-((3x+10))=0

We get rid of parentheses

6x-((3x+10))-19=0



We calculate terms in parentheses: -((3x+10)), so:

(3x+10)

We get rid of parentheses

3x+10

Back to the equation:

-(3x+10)



We get rid of parentheses

6x-3x-10-19=0

We add all the numbers together, and all the variables

3x-29=0

We move all terms containing x to the left, all other terms to the right

3x=29

x=29/3

x=9+2/3

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