(6x-10)=10(x-4)=(4x+5)

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Solution for (6x-10)=10(x-4)=(4x+5) equation: 



(6x-10)=10(x-4)=(4x+5)

We move all terms to the left:

(6x-10)-(10(x-4))=0

We get rid of parentheses

6x-(10(x-4))-10=0



We calculate terms in parentheses: -(10(x-4)), so:

10(x-4)

We multiply parentheses

10x-40

Back to the equation:

-(10x-40)



We get rid of parentheses

6x-10x+40-10=0

We add all the numbers together, and all the variables

-4x+30=0

We move all terms containing x to the left, all other terms to the right

-4x=-30

x=-30/-4

x=7+1/2

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