(6x+7)=(3x+20)+(x+11)

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Solution for (6x+7)=(3x+20)+(x+11) equation: 



(6x+7)=(3x+20)+(x+11)

We move all terms to the left:

(6x+7)-((3x+20)+(x+11))=0

We get rid of parentheses

6x-((3x+20)+(x+11))+7=0



We calculate terms in parentheses: -((3x+20)+(x+11)), so:

(3x+20)+(x+11)

We get rid of parentheses

3x+x+20+11

We add all the numbers together, and all the variables

4x+31

Back to the equation:

-(4x+31)



We get rid of parentheses

6x-4x-31+7=0

We add all the numbers together, and all the variables

2x-24=0

We move all terms containing x to the left, all other terms to the right

2x=24

x=24/2

x=12

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