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(6x+5)=(15+1x)
We move all terms to the left:
(6x+5)-((15+1x))=0
We add all the numbers together, and all the variables
(6x+5)-((x+15))=0
We get rid of parentheses
6x-((x+15))+5=0
We calculate terms in parentheses: -((x+15)), so:We get rid of parentheses
(x+15)
We get rid of parentheses
x+15
Back to the equation:
-(x+15)
6x-x-15+5=0
We add all the numbers together, and all the variables
5x-10=0
We move all terms containing x to the left, all other terms to the right
5x=10
x=10/5
x=2
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