3(2x-1)-4=6x(3x+5)+3

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Solution for 3(2x-1)-4=6x(3x+5)+3 equation: 



3(2x-1)-4=6x(3x+5)+3

We move all terms to the left:

3(2x-1)-4-(6x(3x+5)+3)=0

We multiply parentheses

6x-(6x(3x+5)+3)-3-4=0



We calculate terms in parentheses: -(6x(3x+5)+3), so:

6x(3x+5)+3

We multiply parentheses

18x^2+30x+3

Back to the equation:

-(18x^2+30x+3)



We add all the numbers together, and all the variables

6x-(18x^2+30x+3)-7=0

We get rid of parentheses

-18x^2+6x-30x-3-7=0

We add all the numbers together, and all the variables

-18x^2-24x-10=0

a = -18; b = -24; c = -10;
Δ = b2-4ac
Δ = -242-4·(-18)·(-10)
Δ = -144
Delta is less than zero, so there is no solution for the equation

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