(6x+4)=(10x-54)

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Solution for (6x+4)=(10x-54) equation: 



(6x+4)=(10x-54)

We move all terms to the left:

(6x+4)-((10x-54))=0

We get rid of parentheses

6x-((10x-54))+4=0



We calculate terms in parentheses: -((10x-54)), so:

(10x-54)

We get rid of parentheses

10x-54

Back to the equation:

-(10x-54)



We get rid of parentheses

6x-10x+54+4=0

We add all the numbers together, and all the variables

-4x+58=0

We move all terms containing x to the left, all other terms to the right

-4x=-58

x=-58/-4

x=14+1/2

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