(6x+35)=(20x+11)

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Solution for (6x+35)=(20x+11) equation: 



(6x+35)=(20x+11)

We move all terms to the left:

(6x+35)-((20x+11))=0

We get rid of parentheses

6x-((20x+11))+35=0



We calculate terms in parentheses: -((20x+11)), so:

(20x+11)

We get rid of parentheses

20x+11

Back to the equation:

-(20x+11)



We get rid of parentheses

6x-20x-11+35=0

We add all the numbers together, and all the variables

-14x+24=0

We move all terms containing x to the left, all other terms to the right

-14x=-24

x=-24/-14

x=1+5/7

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