(6x+3)=(9x-33)=180

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Solution for (6x+3)=(9x-33)=180 equation: 



(6x+3)=(9x-33)=180

We move all terms to the left:

(6x+3)-((9x-33))=0

We get rid of parentheses

6x-((9x-33))+3=0



We calculate terms in parentheses: -((9x-33)), so:

(9x-33)

We get rid of parentheses

9x-33

Back to the equation:

-(9x-33)



We get rid of parentheses

6x-9x+33+3=0

We add all the numbers together, and all the variables

-3x+36=0

We move all terms containing x to the left, all other terms to the right

-3x=-36

x=-36/-3

x=+12

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