7/6=2(5-d)/3

Solution for 7/6=2(5-d)/3 equation:

7/6=2(5-d)/3

We move all terms to the left:

7/6-(2(5-d)/3)=0

We add all the numbers together, and all the variables

-(2(-1d+5)/3)+7/6=0

We calculate fractions


(-(2(-1d+5)*6)/()+()/()=0


We calculate terms in parentheses: +(-(2(-1d+5)*6)/()+()/(), so:

-(2(-1d+5)*6)/()+()/(

We add all the numbers together, and all the variables

-(2(-1d+5)*6)/()+1

We multiply all the terms by the denominator


-(2(-1d+5)*6)+1*()


We calculate terms in parentheses: -(2(-1d+5)*6), so:

2(-1d+5)*6

We multiply parentheses

-12d+60

Back to the equation:

-(-12d+60)


We add all the numbers together, and all the variables

-(-12d+60)

We get rid of parentheses

12d-60

Back to the equation:

+(12d-60)


We get rid of parentheses

12d-60=0

We move all terms containing d to the left, all other terms to the right

12d=60

d=60/12

d=5