(6x+20)=(x+40)+(4x-5)

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Solution for (6x+20)=(x+40)+(4x-5) equation: 



(6x+20)=(x+40)+(4x-5)

We move all terms to the left:

(6x+20)-((x+40)+(4x-5))=0

We get rid of parentheses

6x-((x+40)+(4x-5))+20=0



We calculate terms in parentheses: -((x+40)+(4x-5)), so:

(x+40)+(4x-5)

We get rid of parentheses

x+4x+40-5

We add all the numbers together, and all the variables

5x+35

Back to the equation:

-(5x+35)



We get rid of parentheses

6x-5x-35+20=0

We add all the numbers together, and all the variables

x-15=0

We move all terms containing x to the left, all other terms to the right

x=15

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