(6x+2)=(8x-28)

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Solution for (6x+2)=(8x-28) equation: 



(6x+2)=(8x-28)

We move all terms to the left:

(6x+2)-((8x-28))=0

We get rid of parentheses

6x-((8x-28))+2=0



We calculate terms in parentheses: -((8x-28)), so:

(8x-28)

We get rid of parentheses

8x-28

Back to the equation:

-(8x-28)



We get rid of parentheses

6x-8x+28+2=0

We add all the numbers together, and all the variables

-2x+30=0

We move all terms containing x to the left, all other terms to the right

-2x=-30

x=-30/-2

x=+15

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