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(6x+2)(x-3)=(3x+1)(2x-4)+4
We move all terms to the left:
(6x+2)(x-3)-((3x+1)(2x-4)+4)=0
We multiply parentheses ..
(+6x^2-18x+2x-6)-((3x+1)(2x-4)+4)=0
We calculate terms in parentheses: -((3x+1)(2x-4)+4), so:We get rid of parentheses
(3x+1)(2x-4)+4
We multiply parentheses ..
(+6x^2-12x+2x-4)+4
We get rid of parentheses
6x^2-12x+2x-4+4
We add all the numbers together, and all the variables
6x^2-10x
Back to the equation:
-(6x^2-10x)
6x^2-6x^2-18x+2x+10x-6=0
We add all the numbers together, and all the variables
-6x-6=0
We move all terms containing x to the left, all other terms to the right
-6x=6
x=6/-6
x=-1
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