3(x+1)+2(3x-4)=58

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Solution for 3(x+1)+2(3x-4)=58 equation: 



3(x+1)+2(3x-4)=58

We move all terms to the left:

3(x+1)+2(3x-4)-(58)=0

We multiply parentheses

3x+6x+3-8-58=0

We add all the numbers together, and all the variables

9x-63=0

We move all terms containing x to the left, all other terms to the right

9x=63

x=63/9

x=7

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