(6x+12)+16x+4)+(18x+4)=180

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Solution for (6x+12)+16x+4)+(18x+4)=180 equation: 



(6x+12)+16x+4)+(18x+4)=180

We move all terms to the left:

(6x+12)+16x+4)+(18x+4)-(180)=0

We add all the numbers together, and all the variables

16x+(6x+12)+4)+(18x=0

We get rid of parentheses

16x+6x+4)+(18x+12=0

We add all the numbers together, and all the variables

22x+4)+(18x+12=0

We move all terms containing x to the left, all other terms to the right

22x+4)+(18x=-12

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