4x=(2x-6)/10

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Solution for 4x=(2x-6)/10 equation: 



4x=(2x-6)/10

We move all terms to the left:

4x-((2x-6)/10)=0

We multiply all the terms by the denominator


4x*10)-((2x-6)=0

Wy multiply elements

40x^2=0

a = 40; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·40·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{80}=0$

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