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(6x+12)+(x+16)+(2x-19=180
We move all terms to the left:
(6x+12)+(x+16)+(2x-19-(180)=0
We get rid of parentheses
6x+x+(2x-19-180+12+16=0
We add all the numbers together, and all the variables
7x+(2x-19-180+12+16=0
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