6(d+3)=+3(d-5)

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Solution for 6(d+3)=+3(d-5) equation: 



6(d+3)=+3(d-5)

We move all terms to the left:

6(d+3)-(+3(d-5))=0

We multiply parentheses

6d-(+3(d-5))+18=0



We calculate terms in parentheses: -(+3(d-5)), so:

+3(d-5)

determiningTheFunctionDomain
3(d-5)

We multiply parentheses

3d-15

Back to the equation:

-(3d-15)



We get rid of parentheses

6d-3d+15+18=0

We add all the numbers together, and all the variables

3d+33=0

We move all terms containing d to the left, all other terms to the right

3d=-33

d=-33/3

d=-11

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