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(6x+1)(2x+7)=0
We multiply parentheses ..
(+12x^2+42x+2x+7)=0
We get rid of parentheses
12x^2+42x+2x+7=0
We add all the numbers together, and all the variables
12x^2+44x+7=0
a = 12; b = 44; c = +7;
Δ = b2-4ac
Δ = 442-4·12·7
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-40}{2*12}=\frac{-84}{24} =-3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+40}{2*12}=\frac{-4}{24} =-1/6 $
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