(2g+7)(6g+5)=0

Solution for (2g+7)(6g+5)=0 equation:

(2g+7)(6g+5)=0

We multiply parentheses ..

(+12g^2+10g+42g+35)=0

We get rid of parentheses

12g^2+10g+42g+35=0

We add all the numbers together, and all the variables

12g^2+52g+35=0

a = 12; b = 52; c = +35;
Δ = b2-4ac
Δ = 522-4·12·35
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-32}{2*12}=\frac{-84}{24}
=-3+1/2
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+32}{2*12}=\frac{-20}{24}
=-5/6
$