(6x)+(11x-1)=(3x+1)

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Solution for (6x)+(11x-1)=(3x+1) equation: 



(6x)+(11x-1)=(3x+1)

We move all terms to the left:

(6x)+(11x-1)-((3x+1))=0

We get rid of parentheses

6x+11x-((3x+1))-1=0



We calculate terms in parentheses: -((3x+1)), so:

(3x+1)

We get rid of parentheses

3x+1

Back to the equation:

-(3x+1)



We add all the numbers together, and all the variables

17x-(3x+1)-1=0

We get rid of parentheses

17x-3x-1-1=0

We add all the numbers together, and all the variables

14x-2=0

We move all terms containing x to the left, all other terms to the right

14x=2

x=2/14

x=1/7

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